"Mark Tolonen" <[EMAIL PROTECTED]> wrote: >> Can you recommend a generic way to achieve this ? >> Eli > >>>> import os >>>> from os.path import normpath,abspath >>>> x=r'\foo\\bar/baz//spam.py' >>>> normpath(x) > '\\foo\\bar\\baz\\spam.py' >>>> normpath(abspath(x)) > 'C:\\foo\\bar\\baz\\spam.py' >>>> normpath(abspath(x)).split(os.sep) > ['C:', 'foo', 'bar', 'baz', 'spam.py']
That gets a bit messy with UNC pathnames. With the OP's code the double backslah leadin is preserved (although arguably it has split one time too many, '\\\\frodo' would make more sense as the first element: >>> parse_path(r'\\frodo\foo\bar') ['\\\\', 'frodo', 'foo', 'bar'] With your code you just get two empty strings as the leadin: >>> normpath(abspath(r'\\frodo\foo\bar')).split(os.sep) ['', '', 'frodo', 'foo', 'bar'] -- Duncan Booth http://kupuguy.blogspot.com -- http://mail.python.org/mailman/listinfo/python-list
