On Fri, 2008-04-11 at 03:14 -0700, bdsatish wrote: > The built-in function round( ) will always "round up", that is 1.5 is > rounded to 2.0 and 2.5 is rounded to 3.0. > > If I want to round to the nearest even, that is > > my_round(1.5) = 2 # As expected > my_round(2.5) = 2 # Not 3, which is an odd num > > I'm interested in rounding numbers of the form "x.5" depending upon > whether x is odd or even. Any idea about how to implement it ?
This seams to work fine: evenRound = lambda f: round(f/2.)*2 >>> [(f*.5, evenRound(f*.5)) for f in xrange(0,20)] [(0.0, 0.0),(0.5, 0.0), (1.0, 2.0), (1.5, 2.0), (2.0, 2.0), (2.5, 2.0), (3.0, 4.0), (3.5, 4.0), (4.0, 4.0), (4.5, 4.0), (5.0, 6.0), (5.5, 6.0), (6.0, 6.0), (6.5, 6.0), (7.0, 8.0), (7.5, 8.0), (8.0, 8.0), (8.5, 8.0), (9.0, 10.0), (9.5, 10.0)] -- Best Regards, Med Venlig Hilsen, Thomas -- http://mail.python.org/mailman/listinfo/python-list
