On 11 avr, 14:14, Gerard Flanagan <[EMAIL PROTECTED]> wrote: > On Apr 11, 2:05 pm, Gerard Flanagan <[EMAIL PROTECTED]> wrote: > > > On Apr 11, 12:14 pm, bdsatish <[EMAIL PROTECTED]> wrote: > > > > The built-in function round( ) will always "round up", that is 1.5 is > > > rounded to 2.0 and 2.5 is rounded to 3.0. > > > > If I want to round to the nearest even, that is > > > > my_round(1.5) = 2 # As expected > > > my_round(2.5) = 2 # Not 3, which is an odd num > > > > I'm interested in rounding numbers of the form "x.5" depending upon > > > whether x is odd or even. Any idea about how to implement it ?
> In fact you can avoid the call to the builtin round: Alternatively, you can avoid the test using both divmod and round: In [55]: def myround(x): .....: d, m = divmod(x, 2) .....: return 2*d + 1 + round(m-1) .....: In [58]: assert myround(3.2) == 3 In [59]: assert myround(3.6) == 4 In [60]: assert myround(3.5) == 4 In [61]: assert myround(2.5) == 2 In [62]: assert myround(-0.5) == 0.0 In [63]: assert myround(-1.5) == -2.0 In [64]: assert myround(-1.3) == -1.0 In [65]: assert myround(-1.8) == -2 In [66]: assert myround(-2.5) == -2.0 -- http://mail.python.org/mailman/listinfo/python-list
