On Apr 11, 10:29 am, hdante <[EMAIL PROTECTED]> wrote: > Strangely, a "faster" version is: > > def fast_round(x): > if x % 1 != 0.5: return round(x) > return 2.0*round(x/2.0)
You should be a little bit careful with the test x%1 == 0.5 if x might be negative: >>> x = -0.5 + 2**-54 >>> x # not an exact half... -0.49999999999999994 >>> x % 1 # ... and yet x%1 == 0.5 0.5 But for x positive, it should be safe. And for this particular application, it turns out that it doesn't matter: it gives the right result for this input anyway. Mark -- http://mail.python.org/mailman/listinfo/python-list
