On 12 Mar 2005 17:35:50 -0800, "John Machin" <[EMAIL PROTECTED]> wrote:
>
>[EMAIL PROTECTED] wrote:
>>
>> What actually gets transmitted is "C\x01\x02\x10'\x83".
>
>No, that's repr(What actually gets transmitted)
If so, that's 6 bytes, not 18:
>>> "C\x01\x02\x10'\x83"
"C\x01\x02\x10'\x83"
>>> list("C\x01\x02\x10'\x83")
['C', '\x01', '\x02', '\x10', "'", '\x83']
>>> len("C\x01\x02\x10'\x83")
6
OTOH,
>>> list(r"C\x01\x02\x10'\x83")
['C', '\\', 'x', '0', '1', '\\', 'x', '0', '2', '\\', 'x', '1', '0', "'",
'\\', 'x', '8', '3']
>>> len(r"C\x01\x02\x10'\x83")
18
>
>> That's 18 bytes. Is the command supposed to be the ASCII
>> characters \x01 or a single byte whose value is 1?
>
>For a start, according to the OP's code, the command ('C' a.k.a. 67) is
>first. The 1 is a meant to be a message number.
>
>Secondly, the hardware smells like it's got an 8080 or 6502 inside. The
>likelihood that it groks Python/C string representation is minimal.
>Folk just don't send 18 bytes at 9600 bps when 6 bytes will do.
>
Regards,
Bengt Richter
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