Chris Johnson <[EMAIL PROTECTED]> writes: > a = [lambda: i for i in range(10)] > print [f() for f in a] > results in: [9, 9, 9, 9, 9, 9, 9, 9, 9, 9] > rather than the hoped for: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
The usual idiom is a = [lambda i=i: i for i in range(10)] That way i is not a free variable in the lambda. -- http://mail.python.org/mailman/listinfo/python-list
