What I want to do is build an array of lambda functions, like so: a = [lambda: i for i in range(10)]
(This is just a demonstrative dummy array. I don't need better ways to achieve the above functionality.) print [f() for f in a] results in: [9, 9, 9, 9, 9, 9, 9, 9, 9, 9] rather than the hoped for: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] Clearly, lambda is returning the object i, which is left at the last value of range(10). The following is my solution. t = lambda i: lambda: i a = [t(i) for i in range(10)] or the somewhat more terse: a = [(lambda i: lambda: i)(i) for i in range(10)] This gives the behavior which, intuitively, I expected from the original syntax. So my questions are: 1) Does this make sense as what should be done here? That is, would this be the behavior you'd want more often than not? As I said, intuitively, I would think the lambda would treat the iterator variable as a constant in this context. 2) Is there a better or preferred method than the one I've found? Thanks, Chris -- http://mail.python.org/mailman/listinfo/python-list
