On Sep 6, 3:44 am, Paul Rubin <http://[EMAIL PROTECTED]> wrote: > Chris Johnson <[EMAIL PROTECTED]> writes: > > a = [lambda: i for i in range(10)] > > print [f() for f in a] > > results in: [9, 9, 9, 9, 9, 9, 9, 9, 9, 9] > > rather than the hoped for: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] > > The usual idiom is > > a = [lambda i=i: i for i in range(10)] > > That way i is not a free variable in the lambda.
Thanks. I figured there had to be a better way than what I was doing. -- http://mail.python.org/mailman/listinfo/python-list
