Hey many thanks for the replies! Ah, so is seems that c[:][:][:][:][:][:][:][:][:][:][:][0]() also work ...
Ah well, can't have everything. Guess I was inspired by the alphabetically adjacent message "Call for Ruby Champion". Would have been nice for it work - a more elegant iterator would be hard to come by. A PEP, perhaps? Maybe not; am still a bit new - am probably missing something obvious why this isn't an easy fix. Pretty cool that I can override the list class. Cheers, \~/ > -----Original Message----- > From: [EMAIL PROTECTED] [mailto:python-list- > [EMAIL PROTECTED] On Behalf Of Brian van den Broek > Sent: Wednesday, May 30, 2007 3:00 PM > To: python-list@python.org > Subject: Re: c[:]() > > Warren Stringer said unto the world upon 05/30/2007 05:31 PM: > > Hmmm, this is for neither programmer nor computer; this is for a user. > If I > > wanted to write code for the benefit for the computer, I'd still be > flipping > > switches on a PDP-8. ;-) > > > > This is inconsistent: > > > > why does c[:][0]() work but c[:]() does not? > > c[:][0]() says take a copy of the list c, find its first element, and > call it. Since c is a list of functions, that calls a function. > > c[:]() says take a copy of the list c and call it. Since lists are not > callable, that doesn't work. > > > Why does c[0]() has exactly the same results as c[:][0]() ? > > Because c[0] is equal to c[:][0]. > > > Moreover, c[:][0]() implies that a slice was invoked > > Yes, but the complete slice. > > > So, tell me, for scheduling a lot of asynchronous events, what would be > more > > readable than this: > > > > bidders = [local_members] + [callin_members] > > bidders[:].sign_in(roster) > > ... > > for bidder in [local_members] + [callin_members]: > bidder.sign_in(roster) > > Best, > > Brian vdB > > > \~/ > > > >> -----Original Message----- > >> From: [EMAIL PROTECTED] [mailto:python- > list- > >> [EMAIL PROTECTED] On Behalf Of Carsten Haese > >> Sent: Wednesday, May 30, 2007 12:55 PM > >> To: python-list@python.org > >> Subject: Re: c[:]() > >> > >> On Wed, 2007-05-30 at 11:48 -0700, Warren Stringer wrote: > >>> I want to call every object in a tupple, like so: > >>> > >>> #------------------------------------------ > >>> def a: print 'a' > >>> def b: print 'b' > >>> c = (a,b) > >>> > >>>>>> c[:]() # i wanna > >>> [...] > >>> Is there something obvious that I'm missing? > >> Yes: Python is not Perl. > >> > >> Python is based on the principle that programmers don't write computer > >> code for the benefit of the computer, but for the benefit of any > >> programmer who has to read their code in the future. Terseness is not a > >> virtue. To call every function in a tuple, do the obvious: > >> > >> for func in funcs: func() > >> > >> HTH, > >> > >> -- > >> Carsten Haese > >> http://informixdb.sourceforge.net > >> > >> > >> -- > >> http://mail.python.org/mailman/listinfo/python-list > > > > > > -- > http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
