Hmmm, this is for neither programmer nor computer; this is for a user. If I
wanted to write code for the benefit for the computer, I'd still be flipping
switches on a PDP-8. ;-)
This is inconsistent:
why does c[:][0]() work but c[:]() does not?
Why does c[0]() has exactly the same results as c[:][0]() ?
Moreover, c[:][0]() implies that a slice was invoked
So, tell me, for scheduling a lot of asynchronous events, what would be more
readable than this:
bidders = [local_members] + [callin_members]
bidders[:].sign_in(roster)
...
\~/
> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:python-list-
> [EMAIL PROTECTED] On Behalf Of Carsten Haese
> Sent: Wednesday, May 30, 2007 12:55 PM
> To: python-list@python.org
> Subject: Re: c[:]()
>
> On Wed, 2007-05-30 at 11:48 -0700, Warren Stringer wrote:
> > I want to call every object in a tupple, like so:
> >
> > #------------------------------------------
> > def a: print 'a'
> > def b: print 'b'
> > c = (a,b)
> >
> > >>>c[:]() # i wanna
> > [...]
> > Is there something obvious that I'm missing?
>
> Yes: Python is not Perl.
>
> Python is based on the principle that programmers don't write computer
> code for the benefit of the computer, but for the benefit of any
> programmer who has to read their code in the future. Terseness is not a
> virtue. To call every function in a tuple, do the obvious:
>
> for func in funcs: func()
>
> HTH,
>
> --
> Carsten Haese
> http://informixdb.sourceforge.net
>
>
> --
> http://mail.python.org/mailman/listinfo/python-list
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