I tried the following program:
def positive(f):
def call(self, u):
if u < 1:
print 'Not Positive'
raise ValueError
return f(self, u)
return call
class Incrementor:
def __init__(self, val=0):
self.value = val
@positive
def __call__(self, term = 1):
print 'incrementing'
self.value += term
return self.value
inc = Incrementor(0)
try:
print inc(1)
print inc()
print inc(3)
print inc(-2)
except:
pass
And it gave me the following result:
incrementing
1
Now although this behaviour was surprising after somethought
I think I may understand why things go wrong, but I certainly
don't understand the result I got. I would think an error like:
TypeError: call() takes exactly 2 arguments (1 given)
would have been more appropiate.
Am I missing something?
Is it a bug?
Maybe both?
--
Antoon Pardon
--
http://mail.python.org/mailman/listinfo/python-list
