> Now although this behaviour was surprising after somethought
> I think I may understand why things go wrong, but I certainly
> don't understand the result I got. I would think an error like:
>
> TypeError: call() takes exactly 2 arguments (1 given)
>
> would have been more appropiate.
>
>
> Am I missing something?
> Is it a bug?
> Maybe both?
Maybe I'm missing something - but I exactly get that error if I don't use
that try: except: of yours:
For this
-----------------
def positive(f):
def call(self, u):
if u < 1:
print 'Not Positive'
raise ValueError
return f(self, u)
return call
class Incrementor:
def __init__(self, val=0):
self.value = val
@positive
def __call__(self, term = 1):
print 'incrementing'
self.value += term
return self.value
inc = Incrementor(0)
print inc(1)
print inc()
print inc(3)
--------------------
I get this result:
[EMAIL PROTECTED]:~$ python2.4 /tmp/test.py
incrementing
1
Traceback (most recent call last):
File "/tmp/test.py", line 24, in ?
print inc()
TypeError: call() takes exactly 2 arguments (1 give
--
Regards,
Diez B. Roggisch
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