SpreadTooThin wrote:
> If you are deriving a new class from another class,
> that you must (I assume) know the initializer of the other class.
>
> So in myClass
>
> import array
> class myClass(arrary.array):
> def __init__(self, now here I need to put array's constructor
> parameters..., then mine):
> array.array.__init__(self, typecode[, initializer])
> self.mine = mine
>
> So I'm confused...
> array has a typecode parameter and an optional initiializer...
> So could you help me with the class construction here please?
Normally you would do
# won't work
class Array(array.array):
def __init__(self, typecode, initalizer=(), mine=None):
array.array.__init__(self, typecode, initializer)
self.mine = mine
However, array.array is a bit harder to subclass:
# should work
class Array(array.array):
def __new__(cls, typecode, initializer=(), mine=None):
return array.array.__new__(cls, typecode, initializer)
def __init__(self, typecode, initializer=(), mine=None):
array.array.__init__(self, typecode, initializer)
self.mine = mine
See if you can get away by making the array an attribute of your class
instead.
Peter
--
http://mail.python.org/mailman/listinfo/python-list
