Peter Otten wrote: > SpreadTooThin wrote: > > > If you are deriving a new class from another class, > > that you must (I assume) know the initializer of the other class. > > > > So in myClass > > > > import array > > class myClass(arrary.array): > > def __init__(self, now here I need to put array's constructor > > parameters..., then mine): > > array.array.__init__(self, typecode[, initializer]) > > self.mine = mine > > > > So I'm confused... > > array has a typecode parameter and an optional initiializer... > > So could you help me with the class construction here please? > > Normally you would do > > # won't work > class Array(array.array): > def __init__(self, typecode, initalizer=(), mine=None): > array.array.__init__(self, typecode, initializer) > self.mine = mine > > However, array.array is a bit harder to subclass: > > # should work > class Array(array.array): > def __new__(cls, typecode, initializer=(), mine=None): > return array.array.__new__(cls, typecode, initializer) > def __init__(self, typecode, initializer=(), mine=None): > array.array.__init__(self, typecode, initializer) > self.mine = mine > > See if you can get away by making the array an attribute of your class > instead. >
Thanks. the =() syntax indicates what? Just slightly off topic here but if Array had a bunch of initializers of its own, must all the 'optional' parameters be on the right.. ie the last parameters? > Peter -- http://mail.python.org/mailman/listinfo/python-list
