On 3 Oct 2006 19:09:53 -0700, SpreadTooThin <[EMAIL PROTECTED]> wrote: > If you are deriving a new class from another class, > that you must (I assume) know the initializer of the other class. > > So in myClass > > import array > class myClass(arrary.array): > def __init__(self, now here I need to put array's constructor > parameters..., then mine): > array.array.__init__(self, typecode[, initializer]) > self.mine = mine > > So I'm confused... > array has a typecode parameter and an optional initiializer... > So could you help me with the class construction here please?
If you need to take the same parameters as your super-class, and it includes optional positional parameters, then simply call with keywords to avoid the optional parameter: myClass(typecode, mine=something) It has less to do with defining the parameters than calling the function. -- http://mail.python.org/mailman/listinfo/python-list
