> [code]
> import os
>
> def print_tree(start_dir):
> for f in os.listdir(start_dir):
> fp = os.path.join(start_dir, f)
> print fp
> if os.path.isfile(fp): # will return false if use f here!
> if os.path.splitext(fp)[1] == '.html':
> print 'html file found!'
> if os.path.isdir(fp):
> print_tree(fp)
>
> print os.path
> print_tree(r'c:\intent\docn')
> [/code]
>
> As above it all works as expected. However, on the marked
> line, if I use f instead of fp then that condition returns
> false! Surely, isfile(f) should return true, even if I
> just give a filename, rather than the full path?
>
> If anyway can explain this I'd be grateful,
If your current working directory (CWD) is the same as
start_dir, the behaviors of using "f" and "fp" will be the
same. However, if your CWD is *not* the same, "f" is
relative to the CWD, and fp is "start_dir + f" relative to
the CWD.
Thus,
>>> start_dir = 'temp'
>>> os.path.abspath(os.path.curdir)
'/home/tim'
>>> f = 'filename'
>>> fp = os.path.join(start_dir, f)
>>> fp
'temp/filename'
>>> os.path.abspath(f)
'/home/tim/filename'
>>> os.path.abspath(fp)
'/home/tim/temp/filename'
You may also want to read up on os.walk:
for root, dirs, files in os.walk(start_dir):
for f in files:
if os.path.splitext(f)[1].lower()[1:] == 'html':
print 'HTML:', os.path.join(root, f)
#else:
#print 'Not HTML:', os.path.join(root, f)
which allows you to easily do what it looks like your code
is doing.
-tkc
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