Dear Tony, You're not in that directory (start_dir) when the isfile() function is called. See function os.path.curdir() and os.chdir(). Also, you may be confusing the behavior of os.path.walk(), in which the function called will happen once you have been chdired to the directory it is examining.
Hope this was helpful. Yours truly, Rich. -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of codefire Sent: Tuesday, September 19, 2006 1:08 PM To: python-list@python.org Subject: Curious issue with simple code Hi, I have some simple code - which works...kind of..here's the code: [code] import os def print_tree(start_dir): for f in os.listdir(start_dir): fp = os.path.join(start_dir, f) print fp if os.path.isfile(fp): # will return false if use f here! if os.path.splitext(fp)[1] == '.html': print 'html file found!' if os.path.isdir(fp): print_tree(fp) print os.path print_tree(r'c:\intent\docn') [/code] As above it all works as expected. However, on the marked line, if I use f instead of fp then that condition returns false! Surely, isfile(f) should return true, even if I just give a filename, rather than the full path? If anyway can explain this I'd be grateful, Tony -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
