codefire wrote: > Hi, > > I have some simple code - which works...kind of..here's the code: > > [code] > import os > > def print_tree(start_dir): > for f in os.listdir(start_dir): > fp = os.path.join(start_dir, f) > print fp > if os.path.isfile(fp): # will return false if use f here! > if os.path.splitext(fp)[1] == '.html': > print 'html file found!' > if os.path.isdir(fp): > print_tree(fp) > > print os.path > print_tree(r'c:\intent\docn') > [/code] > > As above it all works as expected. However, on the marked line, if I > use f instead of fp then that condition returns false! Surely, > isfile(f) should return true, even if I just give a filename, rather > than the full path?
Of course not, unless a file with that very name exists in the current working directory. Otherwise, where would be the difference between a full-path and the leaf path? Diez -- http://mail.python.org/mailman/listinfo/python-list
