> > In a recent thread, > > http://mail.python.org/pipermail/python-list/2006-September/361512.html, > > a couple of very useful and enlightening itertools examples were given > > and was wondering if my problem also can be solved in an elegant way > > by itertools. > > > > I have a bunch of tuples with varying lengths and would like to have > > all of them the length of the maximal and pad with None's. So > > something like > > > > a = ( 1, 2, 3 ) > > b = ( 10, 20 ) > > c = ( 'x', 'y', 'z', 'e', 'f' ) > > > > should turn into > > > > a = ( 1, 2, 3, None, None ) > > b = ( 10, 20, None, None, None ) > > c = ( 'x', 'y', 'z', 'e', 'f' ) > > > > or maybe a one liner :) > > >>> (a + 5*(None,))[:5] > (1, 2, 3, None, None) > > >>> pad_to = 5 > >>> (a + pad_to*(None,))[:pad_to] > (1, 2, 3, None, None) > >>> (b + pad_to*(None,))[:pad_to] > (10, 20, None, None, None) > >>> (c + pad_to*(None,))[:pad_to] > ('x', 'y', 'z', 'e', 'f') > >>>
Well, something like this is what I actually do. But for this first I have to loop over all tuples and pick out the maximal length, so over all it won't be a one liner but two loops. -- http://mail.python.org/mailman/listinfo/python-list
