George Sakkis a écrit : > Daniel Nogradi wrote: > >>In a recent thread, >>http://mail.python.org/pipermail/python-list/2006-September/361512.html, >>a couple of very useful and enlightening itertools examples were given >>and was wondering if my problem also can be solved in an elegant way >>by itertools. >> >>I have a bunch of tuples with varying lengths and would like to have >>all of them the length of the maximal and pad with None's. So >>something like >> >>a = ( 1, 2, 3 ) >>b = ( 10, 20 ) >>c = ( 'x', 'y', 'z', 'e', 'f' ) >> >>should turn into >> >>a = ( 1, 2, 3, None, None ) >>b = ( 10, 20, None, None, None ) >>c = ( 'x', 'y', 'z', 'e', 'f' ) >> >>Of course with some len( ) calls and loops this can be solved but >>something tells me there is a simple itertools-like solution. >> >>Any ideas? > > > Not the most readable one-liner of all times, but here it goes: > > a,b,c = zip(*map(None,a,b,c)) >
Simple and beautiful - but effectively requires a comment to explain what's going on !-) -- http://mail.python.org/mailman/listinfo/python-list
