Daniel Nogradi wrote: > In a recent thread, > http://mail.python.org/pipermail/python-list/2006-September/361512.html, > a couple of very useful and enlightening itertools examples were given > and was wondering if my problem also can be solved in an elegant way > by itertools. > > I have a bunch of tuples with varying lengths and would like to have > all of them the length of the maximal and pad with None's. So > something like > > a = ( 1, 2, 3 ) > b = ( 10, 20 ) > c = ( 'x', 'y', 'z', 'e', 'f' ) > > should turn into > > a = ( 1, 2, 3, None, None ) > b = ( 10, 20, None, None, None ) > c = ( 'x', 'y', 'z', 'e', 'f' ) > > Of course with some len( ) calls and loops this can be solved but > something tells me there is a simple itertools-like solution. > > Any ideas?
Not the most readable one-liner of all times, but here it goes: a,b,c = zip(*map(None,a,b,c)) George -- http://mail.python.org/mailman/listinfo/python-list
