[EMAIL PROTECTED] wrote: > I have a problem understanding the scope of variable in nested > function. I think I got it nailed to the following example copied from > Learning Python 2nd edition page 205. Here is the code. > > def f1() : > x=88 > f2() > def f2() : > print 'x=',x > f1() > > that returns an error saying that "NameError: global name 'x' is not > defined". I expected f2 to "see" the value of x defined in f1 since it > is nested at runtime. My reading of the book comforted me in this. > > What am I missing? Shouldn't the E of the LEGB rule take care of that. > BTW, I am running this on python 2.3.
For f1 to be seen as the enclosing scope of f2 f2 has to be /defined/ in f1: >>> def f1(): ... x = 88 ... def f2(): ... print "x =", x ... f2() ... >>> f1() x = 88 Just /calling/ a function inside another does not give the inner one access to variables that are visible in the outer. Peter -- http://mail.python.org/mailman/listinfo/python-list
