[EMAIL PROTECTED] wrote: > I have a problem understanding the scope of variable in nested > function. I think I got it nailed to the following example copied from > Learning Python 2nd edition page 205. Here is the code. > > def f1() : > x=88 > f2() > def f2() : > print 'x=',x > f1() > > that returns an error saying that "NameError: global name 'x' is not > defined". I expected f2 to "see" the value of x defined in f1 since it > is nested at runtime. My reading of the book comforted me in this. > > What am I missing? Shouldn't the E of the LEGB rule take care of that.
There's a subtle difference between what you have: >>> def f1() : ... x=88 ... f2() >>> def f2() : ... print 'x=',x >>> f1() [traceback] and >>> def f1(): ... x = 88 ... def f2(): ... print 'x =',x ... f2() ... >>> f1() x = 88 The E in LEGB, as far as I understand it, involves to functions whose *definitions* are nested within another function...not those functions *called* within another function. Craziness ensues with the next example: >>> def f1(): ... x = 99 ... def f2(): ... print 'x =',x ... x = 77 ... f2() ... >>> f1() x = 77 It makes sense...you just have to understand what it's doing. :) -tkc -- http://mail.python.org/mailman/listinfo/python-list
