On Wed, Oct 30, 2002 at 11:26:01AM -0500, Buddha Buck wrote:
> How would you parse:
> 
> @a = @b[[5]];
> 
> (My intent:  for @a; @b -> $x is rw; $y { $x = $y[5] }; # I think... )

I'd write that as @a [=] @b[5];

-Scott
-- 
Jonathan Scott Duff
[EMAIL PROTECTED]

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