David Corbin wrote:
>
> Ariel Scolnicov wrote:
> >
> >
> > So how do I make C<foo> into an array in the first place? Well, I say
> > something like C<foo = (1,2,3)>. But wait -- that's ambiguous! Is
> > C<foo> now a copy of the list (1,2,3) (in which case it's an array),
> > or is it a reference to (1,2,3) (in which case it's a scalar)? In the
> > first case, C<foo = bar> (where C<bar> is an array, assuming I could
> > ever assign an array to a variable) would perform a copy, while in the
> > second it would make the two variables refer to the same thing.
>
> Actually, if you wanted an array, you'd say C<foo = [1,2,3]>. Very
> unambiguous.
ARG! I mean to say if you wanted an array REFERENCE, not an array.
Sorry for the confusion.
>
> >
> > --
> > Ariel Scolnicov |"GCAAGAATTGAACTGTAG" | [EMAIL PROTECTED]
> > Compugen Ltd. |Tel: +972-2-6795059 (Jerusalem) \ We recycle all our Hz
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>
> --
> David Corbin
> Mach Turtle Technologies, Inc.
> http://www.machturtle.com
> [EMAIL PROTECTED]
--
David Corbin
Mach Turtle Technologies, Inc.
http://www.machturtle.com
[EMAIL PROTECTED]
