On Thu, Mar 27, 2003 at 11:42:29PM +0000, Angus Leeming wrote:
> template <class T>
> class B : public T
> {
> public:
> void foo()
> {
> if (emergency_exit)
> ...
> }
> };
>
> > And how would "this->" assist in telling the
> > compiler that it is from the base class (as opposed to the derived class)?
>
> It says that it's a member. Since it's not in B, it has to be in T.
I don't get it, why does the compiler need the this-> hint at all ?
I'm sure he is right but I still don't understand it intuitively.
john
