> | > | Are you saying that member variables must now be accessed with an
> | > | explicit "this->" ? Or only those in base classes? Or only those in
> | > | template classes?
> | >
> | > base classes.
> |
> | Templatized base classes though ? Or something. I'd love to see an
> | explanation (and ... gosh ... even a rationale :)
>
> Go hunt in the gcc gnats database... there you will find both.
I asked on comp.lang.c++. The answer makes intuitive sense but seems to have
engendered a rich stream of "Why? It works with my compiler." answers!
Still the guy in question works for a company that make compilers so I
guess that he 'just knows' ;-)
Angus
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What base class is emergency_exit a member of in the following template
definition?
template <class T>
class B : public T
{
public:
void foo()
{
if (emergency_exit)
...
}
};
> And how would "this->" assist in telling the
> compiler that it is from the base class (as opposed to the derived class)?
It says that it's a member. Since it's not in B, it has to be in T.
> Using "this->" is intended to aid readers of the code, not to resolve
> compiler issues. What compiler requires this?
>
Every conforming one, which is to say very few currently.
Pete Becker
Dinkumware, Ltd.
