On 04/17/2011 06:46 AM, Vincent van Ravesteijn wrote:
On 13-4-2011 16:26, venom00 wrote:+ // Try to cast to the most common widgets and looks in it's content by each + // It's bad OOP, it would be nice to have a QWidget::toString() overloaded by + // each widget, but this would require to change Qt or subclass each widget. + // Note that we have to ignore the amperstand symbol + if (QAbstractButton * button = qobject_cast<QAbstractButton *>(children[child_index])) { + widget_matches = (new QString(button->text()))->replace('&', "") + .contains(search, Qt::CaseInsensitive); + + } else if (QGroupBox * group_box = qobject_cast<QGroupBox *>(children[child_index])) { + widget_matches = (new QString(group_box->title()))->replace('&', "") + .contains(search, Qt::CaseInsensitive); + + } else if (QLabel * label = qobject_cast<QLabel *>(children[child_index])) { + widget_matches = (new QString(label->text()))->replace('&', "") + .contains(search, Qt::CaseInsensitive); + + } else if (QLineEdit * line_edit = qobject_cast<QLineEdit *>(children[child_index])) { + widget_matches = (new QString(line_edit->text()))->replace('&', "") + .contains(search, Qt::CaseInsensitive); + + } else if (QListWidget * list_widget = qobject_cast<QListWidget *>(children[child_index])) { + widget_matches = (list_widget->findItems(search, Qt::MatchContains)).count() != 0; + + } else if (QTreeWidget * tree_view = qobject_cast<QTreeWidget *>(children[child_index])) { + widget_matches = (tree_view->findItems(search, Qt::MatchContains)).count() != 0; + + } else if (QComboBox * combo_box = qobject_cast<QComboBox *>(children[child_index])) { + widget_matches = (combo_box->findText(search, Qt::MatchContains)) != -1; + + } else { + continue; + } +This is really ugly, but I can't think of how to solve it right now.
Would using typeid help a little bit? rh
