Hi, > > I meant to ask... What is the actual goal here? Can you give a little > > background? Maybe there is another way to accomplish what you want to do > > that doesn't rely on cloning the jQuery constructor. > > I want to have both $ and $D; but in $D, I want to override some > functions like 'click', 'hover'. Till now, $ and $D gets overwritten > and so I couldn't use $ or couldn't override $D.click
Is it absolutelly necessary, that $D has all the other jQuery functionality? If not just hav the code you need in $D. Is it absolutelly necessary, that the functions have the name click() and hover()? Maybe you can simply add dclick() and dhover to jQuery. If both are necessary I'd still stick to Michaels question: Why? Sometimes there are other solutions to a problem that one doesn't see untill someone else hits ones nose to it. Tell us why you need it that way and we can think about alternative solutions. Christof
