I want to clone the jQuery object $ to $D; but it actually seems to be overwriting. Can anyone please suggest any solution?
Here is the code: $D = $.extend($); // same result for $D = $; $D.fn.extend({ click: function() { alert('overridden click'); return this; } }); $(document).ready(function(){ $('body').click(); // this also triggers the 'overridden click' -- which is what I want to avoid. $D('body').click(); }); As you see, $('body').click() triggers the 'overridden click', but I wanted it to trigger the original jQuery object's click. -- <?php echo 'Just another PHP saint'; ?> Email: rrjanbiah-at-Y!com Blog: http://rajeshanbiah.blogspot.com/