On May 25, 2:48 am, "R. Rajesh Jeba Anbiah"
<[EMAIL PROTECTED]> wrote:
> I want to clone the jQuery object $ to $D; but it actually seems to be
> overwriting. Can anyone please suggest any solution?
>
> Here is the code:
>
> $D = $.extend($); // same result for $D = $;
> $D.fn.extend({
> click: function() {
> alert('overridden click');
> return this;
> }
> });
>
> $(document).ready(function(){
> $('body').click(); // this also triggers the 'overridden click' --
> which is what I want to avoid.
> $D('body').click();
>
> });
>
> As you see, $('body').click() triggers the 'overridden click', but I
> wanted it to trigger the original jQuery object's click.
Anyone? Or is it impossible (can someone please confirm)?
--
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