On Sunday, May 23, 2021 at 5:04:37 AM UTC-4 axel.wa...@googlemail.com wrote:
> On Sun, May 23, 2021 at 11:02 AM tapi...@gmail.com <tapi...@gmail.com>
> wrote:
>
>> And how to interpret the conflicting messages for the following program?
>>
>
> In one case, `g` is inlined, which is sufficient to prove that its return
> does not escape. But if you only analyse `g` as-is, you must assume that
> the return has to escape, as you don't know what the caller would do with
> is.
>
I also think so. It looks the message "make([]T, N) escapes to heap" in g
means "make([]T, N)" will escape to heap if g is not inlined.
>
>
>>
>> package main
>>
>> type T int
>>
>> const N = 1<<12
>> var i = N - 1
>>
>> func main() {
>> var r = make([]T, N) // make([]T, N) does not escape
>> println(r[i])
>>
>> var r1 = g() // make([]T, N) does not escape
>> println(r1[i])
>>
>> }
>>
>> func g() []T {
>> var ts = make([]T, N) // make([]T, N) escapes to heap
>> return ts
>> }
>>
>> On Sunday, May 23, 2021 at 4:51:30 AM UTC-4 tapi...@gmail.com wrote:
>>
>>> In the following code, "make([]T, n)" is reported as escaped.
>>> But does it really always escape at run time?
>>> Does the report just mean "make([]T, n) possibly escapes to heap"?
>>>
>>> package main
>>>
>>> type T int
>>>
>>> const K = 1<<13
>>> const N = 1<<12
>>> var n = N
>>> var i = n-1
>>>
>>> func main() {
>>> var r = make([]T, N) // make([]T, N) does not escape
>>> println(r[i])
>>>
>>> var r2 = make([]T, n) // make([]T, n) escapes to heap
>>> println(r2[i])
>>>
>>> var r3 = make([]T, K) // make([]T, K) escapes to heap
>>> println(r3[i])
>>> }
>>>
>> --
>>
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