I fix it by :
var w = weighted.NewRandW()
func WeightRandom(services []*registry.Service) Next{
for _, service := range services {
for _,n := range service.Nodes {
w.Add(n,n.Weight)
}
}
return func() (*registry.Node, error) {
n := w.Next()
no, ok := n.(*registry.Node)
if !ok {
return nil,errors.New("get next err")
}
return no, nil
}
}
thx
在 2019年6月27日星期四 UTC+8上午11:16:01，Chou Yan写道：
>
> The situation I am currently experiencing is that it only occur on my
> online app. I try it at local but I can not got the result.
> haha... I make a mistake.
> the code is :
>
> func WeightRandom(services []*registry.Service) Next{
> w := weighted.NewRandW()
> for _, service := range services {
> for _,n := range service.Nodes {
> w.Add(n,n.Weight)
> }
> }
> return func() (*registry.Node, error) {
> n := w.Next()
> no, ok := n.(*registry.Node)
> if !ok {
> return nil,errors.New("get next err")
> }
> return no, nil
> }
> }
>
> The 'rand.New(...SEED)' is outside the loop of for But I neglect that this
> func 'WeightRandom' will be mass goroutine call. so each time.Now().Unix()
> ,the same seed ,the same sequence. So I got mass common rand number.But
> when I change it as time.Now().UnixNano(), the seed will not be the same
> because of the unixnano. so I got correctly. thank you very much
>
> 在 2019年6月27日星期四 UTC+8上午10:52:56，Burak Serdar写道：
>>
>> On Wed, Jun 26, 2019 at 8:48 PM Chou Yan <yan.ch...@gmail.com> wrote:
>> >
>> > like this:
>> > r:=rand.New(rand.NewSource(time.Now().Unix()))
>> > for {
>> > r.Intn(96)
>> > }
>> > I know the same seed will generate the same sequence. But I don't know
>> why it generate mass same number when I use seed of 'time.Now().Unix()',
>> But when I use seed of 'time.Now().UnixNano()', It will not.
>> > I suspect what this is related to the seqence rand algorithm,But I have
>> no relevant evidence
>>
>> This doesn't make sense. Can you reproduce it in the go playground?
>>
>> >
>> > 在 2019年6月27日星期四 UTC+8上午10:32:38，Burak Serdar写道：
>> >>
>> >> On Wed, Jun 26, 2019 at 8:17 PM Chou Yan <yan.ch...@gmail.com> wrote:
>> >> >
>> >> > I use:
>> >> > r:=rand.New(rand.NewSource(time.Now().Unix()))
>> >> > r..Intn(96)
>> >>
>> >> How are you generating multiple random numbers? If your loop that
>> >> generates these numbers include the r:=rand.New(...), then you're
>> >> essentially seeding the random number generator with the same number,
>> >> because the program ends before time.Now().Unix() returns a different
>> >> value every second.
>> >>
>> >> Move the r:=rand.New(...) outsite the for loop.
>> >>
>> >> > I got:
>> >> >
>> >> > and val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 39
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > rand val: 82
>> >> > ...
>> >> > mass common sequential number .
>> >> > But if I change that：
>> >> > r:=rand.New(rand.NewSource(time.Now().UnixNano()))
>> >> > It will not happen.
>> >> > Why does this happened? and how do I choose it between
>> time.Now().Unix() or UnixNano()?
>> >> >
>> >> > --
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>> Groups "golang-nuts" group.
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>> https://groups.google.com/d/msgid/golang-nuts/ce0671c5-f2df-42d9-a7af-bdef939e6d6d%40googlegroups.com.
>>
>>
>> >> > For more options, visit https://groups.google.com/d/optout.
>> >
>> > --
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>>
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>
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