like this:
r:=rand.New(rand.NewSource(time.Now().Unix()))
for {
r.Intn(96)
}
I know the same seed will generate the same sequence. But I don't know why
it generate mass same number when I use seed of 'time.Now().Unix()', But
when I use seed of 'time.Now().UnixNano()', It will not.
I suspect what this is related to the seqence rand algorithm,But I have no
relevant evidence
在 2019年6月27日星期四 UTC+8上午10:32:38，Burak Serdar写道：
>
> On Wed, Jun 26, 2019 at 8:17 PM Chou Yan <yan.ch...@gmail.com
> <javascript:>> wrote:
> >
> > I use:
> > r:=rand.New(rand.NewSource(time.Now().Unix()))
> > r..Intn(96)
>
> How are you generating multiple random numbers? If your loop that
> generates these numbers include the r:=rand.New(...), then you're
> essentially seeding the random number generator with the same number,
> because the program ends before time.Now().Unix() returns a different
> value every second.
>
> Move the r:=rand.New(...) outsite the for loop.
>
> > I got:
> >
> > and val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 39
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > rand val: 82
> > ...
> > mass common sequential number .
> > But if I change that：
> > r:=rand.New(rand.NewSource(time.Now().UnixNano()))
> > It will not happen.
> > Why does this happened? and how do I choose it between time.Now().Unix()
> or UnixNano()?
> >
> > --
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>
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