The situation I am currently experiencing is that it only occur on my
online app. I try it at local but I can not got the result.
haha... I make a mistake.
the code is :
func WeightRandom(services []*registry.Service) Next{
w := weighted.NewRandW()
for _, service := range services {
for _,n := range service.Nodes {
w.Add(n,n.Weight)
}
}
return func() (*registry.Node, error) {
n := w.Next()
no, ok := n.(*registry.Node)
if !ok {
return nil,errors.New("get next err")
}
return no, nil
}
}
The 'rand.New(...SEED)' is outside the loop of for But I neglect that this
func 'WeightRandom' will be mass goroutine call. so each time.Now().Unix()
,the same seed ,the same sequence. So I got mass common rand number.But
when I change it as time.Now().UnixNano(), the seed will not be the same
because of the unixnano. so I got correctly. thank you very much
在 2019年6月27日星期四 UTC+8上午10:52:56，Burak Serdar写道：
>
> On Wed, Jun 26, 2019 at 8:48 PM Chou Yan <yan.ch...@gmail.com
> <javascript:>> wrote:
> >
> > like this:
> > r:=rand.New(rand.NewSource(time.Now().Unix()))
> > for {
> > r.Intn(96)
> > }
> > I know the same seed will generate the same sequence. But I don't know
> why it generate mass same number when I use seed of 'time.Now().Unix()',
> But when I use seed of 'time.Now().UnixNano()', It will not.
> > I suspect what this is related to the seqence rand algorithm,But I have
> no relevant evidence
>
> This doesn't make sense. Can you reproduce it in the go playground?
>
> >
> > 在 2019年6月27日星期四 UTC+8上午10:32:38，Burak Serdar写道：
> >>
> >> On Wed, Jun 26, 2019 at 8:17 PM Chou Yan <yan.ch...@gmail.com> wrote:
> >> >
> >> > I use:
> >> > r:=rand.New(rand.NewSource(time.Now().Unix()))
> >> > r..Intn(96)
> >>
> >> How are you generating multiple random numbers? If your loop that
> >> generates these numbers include the r:=rand.New(...), then you're
> >> essentially seeding the random number generator with the same number,
> >> because the program ends before time.Now().Unix() returns a different
> >> value every second.
> >>
> >> Move the r:=rand.New(...) outsite the for loop.
> >>
> >> > I got:
> >> >
> >> > and val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 39
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > rand val: 82
> >> > ...
> >> > mass common sequential number .
> >> > But if I change that：
> >> > r:=rand.New(rand.NewSource(time.Now().UnixNano()))
> >> > It will not happen.
> >> > Why does this happened? and how do I choose it between
> time.Now().Unix() or UnixNano()?
> >> >
> >> > --
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>
>
> >> > For more options, visit https://groups.google.com/d/optout.
> >
> > --
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>
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