On Thu, Sep 6, 2018 at 9:49 AM Christophe Meessen <
christophe.mees...@gmail.com> wrote:
func f(bool) { ... }
func g() { f(a<b, c>d) }
an similar constructs require unlimited look ahead to distinguish the above
example from something generics. The current Go parser can always decide
where to go based on just the next symbol.
--
-j
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