Thank you very much.
在 2018年3月15日星期四 UTC+8上午7:27:40，Subbu M写道：
>
> Hi,
>
> First Lock - starts the Lock and executes the following statements until
> next Mutex functions are called.
> Here Sync.Mutex I is gloabal, called Unlock in function f().
> As said second lock starts after function f() is executed.
>
> regards
> Subbu
> On Tuesday, March 13, 2018 at 6:27:08 AM UTC-7, 郎凯 wrote:
>>
>> var l sync.Mutex
>> var a string
>>
>> func f() {
>> a = "hello, world"
>> l.Unlock()
>> }
>>
>> func main() {
>> l.Lock()
>> go f()
>> l.Lock()
>> print(a)
>> }
>>
>> I'm a new gopher, reading a blog about lock and having a problem, in
>> general , we use sync.Mutex in pairs, in the above code why could it call
>> lock two times in main.
>> Any help is Appreciated.
>> Thanks in advanced.
>>
>
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