Hi,
First Lock - starts the Lock and executes the following statements until
next Mutex functions are called.
Here Sync.Mutex I is gloabal, called Unlock in function f().
As said second lock starts after function f() is executed.
regards
Subbu
On Tuesday, March 13, 2018 at 6:27:08 AM UTC-7, 郎凯 wrote:
>
> var l sync.Mutex
> var a string
>
> func f() {
> a = "hello, world"
> l.Unlock()
> }
>
> func main() {
> l.Lock()
> go f()
> l.Lock()
> print(a)
> }
>
> I'm a new gopher, reading a blog about lock and having a problem, in
> general , we use sync.Mutex in pairs, in the above code why could it call
> lock two times in main.
> Any help is Appreciated.
> Thanks in advanced.
>
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