The second lock waits until f() runs and unlocks the mutex.
On Tue, Mar 13, 2018 at 3:37 AM, 郎凯 <langkai1...@gmail.com> wrote:
> var l sync.Mutex
> var a string
>
> func f() {
> a = "hello, world"
> l.Unlock()
> }
>
> func main() {
> l.Lock()
> go f()
> l.Lock()
> print(a)
> }
>
> I'm a new gopher, reading a blog about lock and having a problem, in general
> , we use sync.Mutex in pairs, in the above code why could it call lock two
> times in main.
> Any help is Appreciated.
> Thanks in advanced.
>
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