I run example B both playground and my linux(amd64) node, behavior is
different
At playground, function A, B, C run immediately, then program end
immediately
At my linux node, function A, B, C run immediately, but program end after
wait 5 seconds
I confuse why function A and C never sleep 5 seconds during running
playground ?
On Saturday, January 21, 2017 at 11:34:09 AM UTC+8, Rodolfo Azevedo wrote:
>
> Hi all,
>
> I have a question, interesting:
>
> Why the executes is diferente in these both situations?
>
> Execute A:
>
> [11:19]
> ```package main
>
> import (
> "fmt"
> "sync"
> "time"
> )
>
> var wg sync.WaitGroup
>
> func A() {
>
> time.Sleep(time.Second * 5)
> fmt.Println("Função A")
> wg.Done()
>
> }
>
> func B() {
>
> fmt.Println("Função B")
> wg.Done()
>
> }
>
> func C() {
>
> time.Sleep(time.Second * 5)
> fmt.Println("Função C")
> wg.Done()
>
> }
>
> func main() {
>
> wg.Add(3)
> defer wg.Wait()
>
> go A()
> go B()
> go C()
>
> }
> ```
>
> Execute B:
>
> [11:20]
> ```package main
>
> import (
> "fmt"
> "sync"
> "time"
> )
>
> var wg sync.WaitGroup
>
> func A() {
>
> fmt.Println("Função A")
> time.Sleep(time.Second * 5)
> wg.Done()
>
> }
>
> func B() {
>
> fmt.Println("Função B")
> wg.Done()
>
> }
>
> func C() {
>
> fmt.Println("Função C")
> time.Sleep(time.Second * 5)
> wg.Done()
>
> }
>
> func main() {
>
> wg.Add(3)
> defer wg.Wait()
>
> go A()
> go B()
> go C()
>
> }
> ```
>
> [11:21]
> In execute A, function A and C wait 5 seconds, then prints output. In
> execute B no, all the prints executes without respecting time.Sleep.
> Someone can explain why?
>
> [11:22]
> I only change the order of time.Sleep in functions A and C.
>
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