if you get into the fmt.println, you will see the output device is
os.Stdout, any println call will direct output into it nodelay
在 2017年1月21日星期六 UTC+8上午11:34:09，Rodolfo Azevedo写道：
>
> Hi all,
>
> I have a question, interesting:
>
> Why the executes is diferente in these both situations?
>
> Execute A:
>
> [11:19]
> ```package main
>
> import (
> "fmt"
> "sync"
> "time"
> )
>
> var wg sync.WaitGroup
>
> func A() {
>
> time.Sleep(time.Second * 5)
> fmt.Println("Função A")
> wg.Done()
>
> }
>
> func B() {
>
> fmt.Println("Função B")
> wg.Done()
>
> }
>
> func C() {
>
> time.Sleep(time.Second * 5)
> fmt.Println("Função C")
> wg.Done()
>
> }
>
> func main() {
>
> wg.Add(3)
> defer wg.Wait()
>
> go A()
> go B()
> go C()
>
> }
> ```
>
> Execute B:
>
> [11:20]
> ```package main
>
> import (
> "fmt"
> "sync"
> "time"
> )
>
> var wg sync.WaitGroup
>
> func A() {
>
> fmt.Println("Função A")
> time.Sleep(time.Second * 5)
> wg.Done()
>
> }
>
> func B() {
>
> fmt.Println("Função B")
> wg.Done()
>
> }
>
> func C() {
>
> fmt.Println("Função C")
> time.Sleep(time.Second * 5)
> wg.Done()
>
> }
>
> func main() {
>
> wg.Add(3)
> defer wg.Wait()
>
> go A()
> go B()
> go C()
>
> }
> ```
>
> [11:21]
> In execute A, function A and C wait 5 seconds, then prints output. In
> execute B no, all the prints executes without respecting time.Sleep.
> Someone can explain why?
>
> [11:22]
> I only change the order of time.Sleep in functions A and C.
>
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