On Fri, Jan 20, 2017 at 7:34 PM, Rodolfo Azevedo <rof20...@gmail.com> wrote:
>
> I have a question, interesting:
>
> Why the executes is diferente in these both situations?
>
> Execute A:
>
> [11:19]
> ```package main
>
> import (
> "fmt"
> "sync"
> "time"
> )
>
> var wg sync.WaitGroup
>
> func A() {
>
> time.Sleep(time.Second * 5)
> fmt.Println("Função A")
> wg.Done()
>
> }
>
> func B() {
>
> fmt.Println("Função B")
> wg.Done()
>
> }
>
> func C() {
>
> time.Sleep(time.Second * 5)
> fmt.Println("Função C")
> wg.Done()
>
> }
>
> func main() {
>
> wg.Add(3)
> defer wg.Wait()
>
> go A()
> go B()
> go C()
>
> }
> ```
>
> Execute B:
>
> [11:20]
> ```package main
>
> import (
> "fmt"
> "sync"
> "time"
> )
>
> var wg sync.WaitGroup
>
> func A() {
>
> fmt.Println("Função A")
> time.Sleep(time.Second * 5)
> wg.Done()
>
> }
>
> func B() {
>
> fmt.Println("Função B")
> wg.Done()
>
> }
>
> func C() {
>
> fmt.Println("Função C")
> time.Sleep(time.Second * 5)
> wg.Done()
>
> }
>
> func main() {
>
> wg.Add(3)
> defer wg.Wait()
>
> go A()
> go B()
> go C()
>
> }
> ```
>
> [11:21]
> In execute A, function A and C wait 5 seconds, then prints output. In
> execute B no, all the prints executes without respecting time.Sleep. Someone
> can explain why?
>
> [11:22]
> I only change the order of time.Sleep in functions A and C.
I don't understand the question. In "execute B", functions A and C
print and then sleep. It sounds like you are seeing exactly what I
would expect you to see. What exactly do you see, and what exactly do
you expect to see instead?
Ian
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