Konstantin Vladimirov wrote: [...] > x = (y & ~(1 << 7)) | (((value >> 9) & 1) << 7); [...] > x = y & 4294967167 | (value >> 9) << 7 & 255; <--------- WAT?
((value >> 9) & 1) << 7 == ((value >> 9) << 7) & (1 << 7) == ((value >> 9) << 7) & 0x80 == ((value >> 9) << 7) & 0xff ...I think. That last step is probably being done because anding with 0xff is really cheap on x86 (you just pick the appropriate subreg --- al instead of eax, for example). -- ┌─── ｄｇ＠ｃｏｗｌａｒｋ．ｃｏｍ ───── http://www.cowlark.com ───── │ "USER'S MANUAL VERSION 1.0: The information presented in this │ publication has been carefully for reliability." --- anonymous │ computer hardware manual
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