Pedro Pedruzzi <pedro.pedru...@gmail.com> writes:
> On Thu, Oct 6, 2011 at 11:04 AM, Miles Bader <mi...@gnu.org> wrote:
>> How about:
>>
>> bool overflowbit2(unsigned int a, unsigned int b)
>> {
>> const unsigned int sum = a + b;
>> return ~(a ^ b) & sum & 0x80;
>> }
>
> Miles, it is not the same. Take for example (0xff, 0xff). In 8-bit
> 2's complement, this is (-1, -1) and does not overflow. Your
> function says it does.
Negative overflow isn't considered overflow...? wacky...
-miles
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