On Tue, Jun 13, 2006 at 10:37:29AM +0000, [EMAIL PROTECTED] wrote:
> On Mon, Jun 12, 2006 at 04:59:04PM -0700, Ian Lance Taylor wrote:
> >
> > Probably better to say that these are read-write operands, using the
> > '+' constraint.
> >
> > > Now everything works fine at -O3. However, I really don't understand
> > > the '&' early clobber constraint modifer. What use is it?
> >
> > It is needed for assembly code which has both outputs and inputs, and
> > which includes more than one instruction, such that at least one of
> > the outputs is generated by an instruction which runs before another
> > instruction which requires one of the inputs. The '&' constraint
> > tells gcc that some of the output operands are produced before some of
> > the input operands are used. gcc will then avoid allocating the input
> > and output operands to the same register.
> >
>
> Ian, thanks for the reply.
>
> So, in conclusion, a correct longcpy() would look like this:
>
> void longcpy(long* _dst, long* _src, unsigned _numwords)
> {
> asm volatile (
> "cld \n\t"
> "rep \n\t"
> "movsl \n\t"
> // Outputs (read/write)
> : "+S" (_src), "+D" (_dst), "+c" (_numwords)
> // Inputs - specify same registers as outputs
> : "0" (_src), "1" (_dst), "2" (_numwords)
> // Clobbers: direction flag, so "cc", and "memory"
> : "cc", "memory"
> );
> }
>
Which doesn't compile ;(
The correct version is I think,
void longcpy(long* _dst, long* _src, unsigned _numwords)
{
asm volatile (
"cld \n\t"
"rep \n\t"
"movsl \n\t"
// Outputs (read/write)
: "=S" (_src), "=D" (_dst), "=c" (_numwords)
// Inputs - specify same registers as outputs
: "0" (_src), "1" (_dst), "2" (_numwords)
// Clobbers: direction flag, so "cc", and "memory"
: "cc", "memory"
);
}
> Thanks
>
> Andrew Walrond
