Vincent Lefevre <[EMAIL PROTECTED]> writes: | On 2005-04-27 12:29:53 +0100, Andrew Haley wrote: | > Vincent Lefevre writes: | > > The only two constraints in 6.6 are: | > > | > > [#3] Constant expressions shall not contain assignment, | > > increment, decrement, function-call, or comma operators, | > > except when they are contained within a subexpression that | > > is not evaluated.86) | > > | > > [#4] Each constant expression shall evaluate to a constant | > > that is in the range of representable values for its type. | > > | > > #3 doesn't include variables. #4 is OK if one considers that the | > > value cannot be modified. | > > | > > #6 adds other requirements, but this is out of the scope of the | > > given diagnostic (which complained about an expression not being a | > > constant -- not because it wasn't an integer constant expression). | > | > 6.7.8 Para 4. All the expressions for an initializer for an object | > that has static storage duration shall be constant expressions ... | ^^^^^^^^^^^^^^^^^^^^ | It is said "constant expressions", not "integer constant expressions".
And an integer constant expression is not a constant expression in your copy of the C standard? | > 6.6 Para 6. An integer constant expression shall have integer type | ^^^^^^^^^^^^^^^^^^^^^^^^^^^ | > and shall only have operands that are inetger constants, enumeration | > constants, character constants, sizeof expressions whose results are | > integer constants, and floating-point constans that are the | > immediate operands of casts ... | | #6 is about an *integer* constant expression. And? -- Gaby
