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Duncan Sands wrote:
| On Mon, 2005-03-07 at 10:51 -0500, Robert Dewar wrote:
|
|>Paolo Carlini wrote:
|>
|>>Andrew Haley wrote:
|>>
|>>
|>>>F9.4.4 requires pow (x, 0) to return 1 for any x, even NaN.
|>>>
|>>>
|>>
|>>Indeed. My point, basically, is that consistency appear to require the
|>>very same behavior for *complex* zero^zero.
|>
|>I am not sure, it looks like the standard is deliberately vague here,
|>and is not requiring this result.
|
|
| Mathematically speaking zero^zero is undefined, so it should be NaN.
| This already clear for real numbers: consider x^0 where x decreases
| to zero.  This is always 1, so you could deduce that 0^0 should be 1.
| However, consider 0^x where x decreases to zero.  This is always 0, so
| you could deduce that 0^0 should be 0.  In fact the limit of x^y
| where x and y decrease to 0 does not exist, even if you exclude the
| degenerate cases where x=0 or y=0.  This is why there is no reasonable
| mathematical value for 0^0.
|

That is true.

However, on the other hand, however the standard says looks to me to say
0^0=1. Also printf("%f",pow(0.0,0.0)) returns 1.0 on both VC++6 and g++
3.3 (just what I happen to have lying around..)

I would agree with Paolo that the most imporant point is arguably
consistency, and it looks like that is pow(0.0,0.0)=1

Chris
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