> Hello, > > I noticed that, with FPC 1.9.4, the (default) calling convention > "register" depends on the fact that a routine is or is not embedded > in an other routine. > > With "proc(A,B,C: Longint);", if "proc" is not embedded then > eax = A, edx = B and ecx = C but if "proc" is embedded then edx = A, > ecx = B and C is on the stack. > > Is this convention definitive or temporary? I am not sure it is > definitive since it makes the code of assembler routines dependent > on their status: embedded or not.
The framepointer of the parent function is passed in EAX _______________________________________________ fpc-pascal maillist - [EMAIL PROTECTED] http://lists.freepascal.org/mailman/listinfo/fpc-pascal
