Hello,
I noticed that, with FPC 1.9.4, the (default) calling convention "register" depends on the fact that a routine is or is not embedded in an other routine.
With "proc(A,B,C: Longint);", if "proc" is not embedded then eax = A, edx = B and ecx = C but if "proc" is embedded then edx = A, ecx = B and C is on the stack.
Is this convention definitive or temporary? I am not sure it is definitive since it makes the code of assembler routines dependent on their status: embedded or not.
This is exactly the same as Delphi (7) behaves.
procedure nx_fill(P: PLongword; Count: Longint; Value: Longword); assembler; asm pushl %edi movl %eax,%edi // edi <- P movl %ecx,%eax // eax <- Value movl %edx,%ecx // ecx <- Count rep stosl popl %edi end;
In this case
procedure nx_fill(P: PLongword; Count: Longint; Value: Longword);
assembler;
asm
pushl %edi
movl P,%edi // edi <- P
movl Value,%eax // eax <- Value
movl Count,%ecx // ecx <- Count
rep
stosl
popl %edi
end;works both as embedded and non-embedded assembler procedure because the order of assignments is ok in both cases.
Btw, there's already a method in the system unit which does the same thing as your routine: filldword()...
Regards, Thomas
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