Hello, I noticed that, with FPC 1.9.4, the (default) calling convention "register" depends on the fact that a routine is or is not embedded in an other routine.
With "proc(A,B,C: Longint);", if "proc" is not embedded then eax = A, edx = B and ecx = C but if "proc" is embedded then edx = A, ecx = B and C is on the stack. Is this convention definitive or temporary? I am not sure it is definitive since it makes the code of assembler routines dependent on their status: embedded or not. Thanks, -- mm http://www.ellipsa.net/ _______________________________________________ fpc-pascal maillist - [EMAIL PROTECTED] http://lists.freepascal.org/mailman/listinfo/fpc-pascal
